Question

Find the volume of a solid with base in the region bounded by y = x^2 and y = 4, and with cross-sections perpendicular to the x-axis that are equilateral triangles with sides of length 2x.

Answer 1

the volume of the solid is 16 units^3

Explanation:

Answer 2

Explanation:

To find the volume of this solid, we will use the method of cylindrical shells. We will integrate the cross-sectional area of the equilateral triangles over the height of the solid.

The height of the solid is given by the difference between the upper and lower bounds of the base, which are y = 4 and y = x^2, respectively. The cross-sectional area of an equilateral triangle with sides of length 2x is given by (x^2 * √3)/4.

So, the volume of the solid is given by the integral:

V = ∫[x^2, 4] (x^2 * √3)/4 dx

Using the antiderivative of x^2 * √3 / 4, which is (2x^3 * √3)/(12), we can find the definite integral:

V = [2x^3 * √3]/12 from x^2 to 4

Evaluating the definite integral and simplifying, we get:

V = 16 units^3

So, the volume of the solid is 16 units^3.