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A cone has a volume of 8 pi cubic inches what is the radius of the cone?

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Answer:


r = \sqrt{(24)/(h)} inches

Explanation:

Volume of a cone =
(1)/(3) \pi r^(3)h

where: r = radius of cone

h = perpendicular height of the cone

Provided volume of cone = 8π cubic inches


8\pi = (1)/(3)\pi r^(2) h

Cross multiplication is applied and 'r' is isolated:


3(8\pi ) = \pi r^(2) h


24\pi =\pi r^(2) h


r^(2) h = (24\pi)/(\pi)


\pi in the numerator and denominator cancel each other out completely:


r^(2) h = 24


r^(2) = (24)/(h)

Taking the square root on both sides of the equation in order to get rid of the square:


r = \sqrt{(24)/(h)} inches

User Rbedger
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