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let x represent one number and let y represent the other number. use the given conditions to write a system of equations. solve the system and find the numbers. three times a first number decreased by a second number is 22. the first number increased by twice the second number is 12.

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Answer:

(x, y) = (8, 2)

Explanation:

The relevant equations are ...

3x -y = 22

x +2y = 12

__

We can eliminate y by adding twice the first equation to the second.

2(3x -y) +(x +2y) = 2(22) +(12)

7x = 56

x = 8

Substituting into the first equation gives ...

3(8) -y = 22

y = 24 -22 = 2

The first number is 8; the second number is 2.

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