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a trian traveling at 20kmph is accelerated at the rate of 0.5meters squared . what is the distance travelled by the train in 12 second's​

User Zinking
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1 Answer

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Answer:

The distance traveled by train in 12 seconds is 66.72 meters.

Step-by-step explanation:

The acceleration rate given is in meters per second squared, so we need to convert the velocity of the train to meters per second.

20 km/hr = (20 x 1000)/(60 x 60) = 5.56 m/s

Now we can use the formula for displacement with constant acceleration:

d = v₀t + 0.5at²

where

v₀ = initial velocity = 5.56 m/s

t = time = 12 s

a = acceleration = 0.5 m/s²

Substituting the values, we get:

d = 5.56 x 12 + 0.5 x 0.5 x 12²

d = 66.72 m

User Megan
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