Answer:
The distance traveled by train in 12 seconds is 66.72 meters.
Step-by-step explanation:
The acceleration rate given is in meters per second squared, so we need to convert the velocity of the train to meters per second.
20 km/hr = (20 x 1000)/(60 x 60) = 5.56 m/s
Now we can use the formula for displacement with constant acceleration:
d = v₀t + 0.5at²
where
v₀ = initial velocity = 5.56 m/s
t = time = 12 s
a = acceleration = 0.5 m/s²
Substituting the values, we get:
d = 5.56 x 12 + 0.5 x 0.5 x 12²
d = 66.72 m