Question

Find the zero(s) of the following polynomial

a) O-18, 18
b) 0-3√2
c) 03√2
d) O-3√2, 3√/2
e) 0,3√2
f) None of the above
P(x) = x^2- 18

Answer 1

-1, 1 5/3 and 5/3

Explanation:

Two zeroes are 35 and −35

So we can write it as, x = 35 and x = −35

we get x−35=0 and x+35=0

Multiply both the factors we get,

x2−35=0

Multiply by 3 we get

3x2−5=0 is the factor of 3x4+6x3−2x2−10x−5

Now divide, 3x4+6x3−2x2−10x−5 by 3x2−5=0 we get,

Quotient is x2+2x+1=0

Compare the equation with quadratic formula,

x2−(S