87.2k views
4 votes
If ST = p + 31, RU = 6p + 14, and VW = 4p + 53, what is the value of p?

If ST = p + 31, RU = 6p + 14, and VW = 4p + 53, what is the value of p?-example-1
User Wmeyer
by
7.4k points

1 Answer

2 votes

Answer:

If we subtract 14 from both sides of the equation for RU, we get 6p = RU - 14, or 6p = RU - 14. We can then substitute this expression for 6p into the equation for ST to get:

ST = p + 31

ST = (RU - 14) + 31

Expanding RU, we get:

ST = RU - 14 + 31

ST = RU + 17

Since RU = 6p + 14, we can substitute this expression into the above equation to solve for p:

ST = 6p + 14 + 17

ST = 6p + 31

Finally, we can subtract 31 from both sides of the equation to find p:

ST - 31 = 6p + 31 - 31

ST - 31 = 6p

ST - 31 = 6p

p = (ST - 31) / 6

So, to find the value of p, we need to know the value of ST.

User Muhammad Kamal
by
8.1k points