Answer: a. The area of the rectangular base of the bale of hay is 2 feet * 3 feet = 6 square feet.
The area of the circular base of the bucket is π * (diameter/2)^2, where the diameter is 3 feet, so the area is π * (3/2)^2 = π * (9/4) = 9π/4 square feet.
Since π is approximately equal to 3.14, the area of the circular base is approximately 9 * 3.14 / 4 = 6.935 square feet, which is less than the area of the rectangular base.
So the rectangular base of the bale of hay is larger in area.
b. The volume of the bale of hay is 2 feet * 3 feet * 5 feet = 30 cubic feet.
The volume of the bucket is π * (diameter/2)^2 * height, where the diameter is 3 feet and the height is 5 feet, so the volume is π * (3/2)^2 * 5 = π * (9/4) * 5 = 45π/4 cubic feet.
Since π is approximately equal to 3.14, the volume of the bucket is approximately 45 * 3.14 / 4 = 34.65 cubic feet, which is less than the volume of the bale of hay.
So the bale of hay is larger in volume.
Explanation: