Question

Linear equation that passes through the points of (-12,14) and (6,-1)

ASAP PLS

Answer 1

First you need to find the slope of the line joining the two points

Slope =
`((14-(-1)))/(((-12)-6))` =
`(15)/(-18)`

then find the equation

y-(-1) = 15/-18 (x-6)

y+1 = 15/-18 x +5

y = -15/18 x + 4

you can present the equation in the above way or multiply the whole equation by 18 if you do not want any fractions

Answer 2

y = -15/18 x - 12

Explanation:

The linear equation that passes through the points (-12, 14) and (6, -1) can be found by using the point-slope form of a line. The point-slope form of a line is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line, m is the slope of the line, and (x, y) are the coordinates of any other point on the line. To find the equation of the line passing through the points (-12, 14) and (6, -1), we can use either of the two points as (x1, y1) and find the slope m using the other point.

Let's use the point (-12, 14) as (x1, y1):

m = (y2 - y1) / (x2 - x1)

= (-1 - 14) / (6 + 12)

= -15/18

y - 14 = -15/18 (x + 12)

Simplifying the equation, we get:

y = -15/18 x - 12

This is the linear equation that passes through the points (-12, 14) and (6, -1).