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Write an equation of the line that passes through (-4,-1) and is perpendicular to the line y=x+6

User Quana
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Answer:

y = -x + 5

Explanation:

To find the equation of the line that is perpendicular to the line y = x + 6 and passes through the point (-4, -1), we'll use the slope-point form of the equation of a line. The slope of a line perpendicular to y = x + 6 is -1, which we can find using the negative reciprocal of the slope of y = x + 6. The slope of y = x + 6 is 1. The negative reciprocal of 1 is -1.

So the equation of the line perpendicular to y = x + 6 that passes through the point (-4, -1) is given by:

y - (-1) = -1(x - (-4))

Expanding and simplifying the right-hand side, we get:

y + 1 = -x + 4

y = -x + 5

User Sedeh
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