well, looking at the picture above, we can see that the diameters are 12.5 and 3.5 for those circles, that means the radii for them will be half that for each, namely 6.25 and 1.75 respectively.
let's get the whole area for containing circle, and then subtract the area of the small ones, what's leftover is the shaded area.
![\stackrel{large~one}{\textit{area of a circle}}\\\\ A=\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6.25 \end{cases}\implies A=\pi 6.25^2 \\\\\\ \stackrel{small~one}{\textit{area of a circle}}\\\\ A=\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=1.75 \end{cases}\implies A=\pi 1.75^2 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\LARGE Areas}}{\stackrel{large}{\pi 6.25^2}~~ - ~~\stackrel{\textit{two small ones}}{2(\pi 1.75^2)}} ~~ \approx ~~ \text{\LARGE 103.48}](https://img.qammunity.org/2024/formulas/mathematics/high-school/xovnsmntu54auklg92xcr1u3th6qbqhiaf.png)