Question

Can someone tell me answer for this question? please

Answer 1

see below

Explanation:

3540/3820 = 93%

so 7% decline

if linearly = every year decline 7%

so back in 1990, 3 years ago, the population was

p° = 3820/(1-7%)^3 =3820/.8=4749

so from 1990

p = 4749 * (1-7%)^t

2009 is 16 years from 1993

so p = 3820 * (1-7%)^16 =1196

Answer 2

A) P(t) = 3820 -70t

B) 2700

Explanation:

You want a linear equation for the moose population that changed from 3820 in 1993 to 3540 in 1997, and you want the predicted population in 2009.

A)

The slope of the linear function can be found from ...

m = (p2 -p1)/(t2 -t1)

If we let t represent years after 1993, then this is ...

m = (3540 -3820)/(4 -0) = -280/4 = -70

P(t) = 3820 -70t . . . . . . . . population is 3820 when t=0, 70 less each year

B)

2009 is 16 years after 1993, so we want P(16):

P(16) = 3820 -70·16 = 3820 -1120

P(16) = 2700

The population is predicted to be 2700 in 2009.