Answer:
Explanation:
To find the equation of a line that is parallel to another line, we can use the same slope for both lines. The slope of the line with the equation -14x + 3y = -4 can be found by rearranging the equation into slope-intercept form:
y = -14/3x - 4/3
The slope of this line is -14/3.
To find the equation of a line that passes through the point (2,-6) with the same slope, we can use the point-slope form of a line:
y - y1 = m(x - x1)
Where:
m is the slope of the line
(x1, y1) is a point on the line
Plugging in the values from the given information:
m = -14/3
x1 = 2
y1 = -6
y - (-6) = -14/3 (x - 2)
y + 6 = -14/3x + 14
So the equation of the line through the point (2,-6) that is parallel to the line with the equation -14x + 3y = -4 is:
y + 6 = -14/3x + 14.