Question

1. Y is 200m North of X and Z is 200m East of Y. Find the bearing of Z from X

2. A man walks 800m on a bearing of 120°. calculate how far from east he is from his starting point ​

Answer 1

1. XZ = √(200²+200²) =√2*200 = 282.8m

2. Not sure

Explanation:

Answer 2

see below

Explanation:

1. XZ = √(200²+200²) =√2*200 = 282.8m

2. if the man started from 0,0 point & walks 120° meaning he's walking towards the northwest, so he'll be 400m west and 400√3 = 693m north from his starting point, because 120° -90° = 30° you are basically solving a problem of 3 sides length of a special straight triangle with an angle of 30. this type of triangle has a property of shorter side = 1/2 of the long side. 2nd shorter side = √3/2 of the long side. this, you should memorize. which will make lots of problems a piece of cake. good luck