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Write the equation of the circle centered at (-1,-5) that passes through (0,-18)

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Answer:

(x + 1)^2 + (y + 5)^2 = 169

Explanation:

The equation of a circle centered at (h,k) with radius r is given by:

(x - h)^2 + (y - k)^2 = r^2

To find the equation of the circle, we first need to find the center and the radius.

Given that the circle is centered at (-1,-5), h = -1 and k = -5.

Next, we need to find the radius. To do this, we use the point (0,-18) that lies on the circle and use the distance formula:

r = sqrt[ (0-(-1))^2 + (-18-(-5))^2 ] = sqrt[ 1^2 + (13)^2 ] = sqrt[1 + 169] = sqrt[170] = 13

So, the equation of the circle is:

(x + 1)^2 + (y + 5)^2 = 13^2

Therefore, the equation of the circle centered at (-1,-5) that passes through (0,-18) is:

(x + 1)^2 + (y + 5)^2 = 169

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