Question

Balance the chemical equations

Answer 1

1.
`2NaI + F_(2) = 2NaF + I_(2)`

2.
`3Ca + N_(2) = Ca_(3) N_(2)`

3.
`Pb(ClO_(2))_(4) + 2Zn(SO_(4) ) = Pb(SO_(4))_(2) + 2Zn(ClO_(2))_(2)`

4.
`2Li(OH) = Li_(2)O + H_(2)O`

5.
`4Cr + 3O_(2) = 2Cr_(2)O_(3)`

Step-by-step explanation:

These are all done similarly so I will just work out problem 3 because it is the hardest.

Start with the first part

`Pb(ClO_(2))_(4)`

We see that there is one Pb and looking at the other side of the equation there is also only one. Next, there are 4 Cl, and on the other side there are only two so to make it even, we multiply the last part by 2 so we will have:

`2Zn(ClO_(2))_(2)`

Now looking back at the first part, have 8 O, and in the second part 4 O so we have 12 O on the left side of the equation. on the right there are 8 O and 8 O so that is 16 O. To make that even, multiply the second part by 2 to get 8 O. Now there will be 2 Zn on each side and 2 S.

So we get the equation:

`Pb(ClO_(2))_(4) + 2Zn(SO_(4)) = Pb(SO_(4))_(2) + 2Zn(ClO_(2))_(2)`