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2) Three positive charges are located as shown in the diagram below q1 1cm q3 q1 1cm q2 find the size of electrostatic force exerted by charge q3.​

1 Answer

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To find the electrostatic force exerted by charge q3 on charge q1, we can use Coulomb's law:

F = k * (q1 * q3) / r^2

where:

k is Coulomb's constant (8.99 x 10^9 N * m^2 / C^2)
q1 and q3 are the magnitudes of charges 1 and 3 (assumed to be in Coulombs)
r is the distance between the charges (1 cm in this case)
So the force can be calculated as:

F = 8.99 x 10^9 N * m^2 / C^2 * (q1 * q3) / (1 cm)^2

Plugging in the numbers, assuming q1 and q3 are both 1 Coulomb each:

F = 8.99 x 10^9 N * m^2 / C^2 * (1 Coulomb * 1 Coulomb) / (1 cm)^2
= 8.99 x 10^9 N

The electrostatic force between the two charges is 8.99 x 10^9 N.
User Janoz
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