Question

A 0.600-kg ball traveling at 4.00 m/s to the right collides with a 1.00-kg ball traveling at 5.00 m/s to the left. After the collision, the lighter ball is traveling 7.25 m/s to the left. What is the velocity of the heavier ball after the collision?​

Answer 1

Step-by-step explanation:

Step 1: Let the velocity of the heavier ball be V.

Step 2: Set up the equation for momentum conservation.

0.6*4 + 1.0*(-5) = 0.6*V + 1.0*7.25

Step 3: Solve the equation for V.

0.6*4 + 1.0*(-5) = 0.6*V + 1.0*7.25

0.6*4 - 1.0*7.25 = 0.6*V - 1.0*5

2.4 - 7.25 = 0.6V - 5

-4.85 = 0.6V

V = -4.85/0.6

V = -8.08 m/s

Answer 2

The velocity of the heavier ball after the collision is 3.05 m/s

Step-by-step explanation:

My explanation is included the pictures attached below