Question

How many Joules of heat are required to melt 250 grams of ice at 0°C?

AHfus = 334 J/g
AHvap = 2258 J/g
Cp= 4.184 J/g C

Answer 1

cp =4.184/c / j

Step-by-step explanation:

ahvap=2258j/g

Answer 2

Heat required : Q = 83500 J = 83.5 kJ

Further explanation

Given

mass ice = 250 g at 0°C

Required

The heat required

Solution

The heat to change the phase can be formulated :

Q = m.Lf (melting/freezing)

Lf=latent heat of fusion

Input the value :

Q = 250 g x 334 J/g

Q = 83500 J