Question

A rectangular field is six times as long as it is wide. If the perimeter of the field is

770 feet, what are the dimensions of the field?
A) Write an equation you can
to answer the given question lot an be the width

Answer 1

the width = 55 feet and the length = 330 feet

so basically we take the width as x and the length as 6x then since the perimeter of a rectangle = 2*width + 2*length we will form the equation 6x + 6x + x + x = 770
then we'll solve this equation
14x = 770
x = 55
then multiply x by 6 to get the length which is 330

Answer 2

6W + W = 770
==> 7W = 770

W = 110 and L = 660 in case you are looking for the solution

Explanation:

Let L -= length and W the width of the rectangular field

six times as long as it is wide translates to:
L = 6W

Perimeter of field = 2(L + W)

Given perimeter = 770 feet
2(L + W) = 770
L + W = 770/2 = 385

Since L = 6W, substitute for L in the above equation:
6W + W = 770

7W = 770

W = 770/7 = 110 feet

L = 6W = 6(110) = 660 feet