Explanation:
The definite integral of (sin(x))^3 from 0 to π can be evaluated using a trigonometric identity.
∫_0^π (sin(x))^3 dx = -cos(x)(sin(x))^2 |_0^π
Using the fact that sin(0) = 0 and sin(π) = 0, we have:
-cos(x)(sin(x))^2 |_0^π = -cos(π)(sin(π))^2 + cos(0)(sin(0))^2
= 0 - (-1)(0)^2 = 0
Therefore, the definite integral of (sin(x))^3 from 0 to π is equal to 0.