Question

hile watching a car move down the street, you close your eyes and count off 15 seconds. When you open your eyes again, the car is 144 feet further down the road from when you last saw it.WHAT IF the car traveled at a constant speed while your eyes were closed - how fast would it have had to travel?a. What constant speed would allow the car to travel exactly 144 feet in exactly 15 seconds?Select an answer second ft/sec feetb. If a car traveled at this speed for tt seconds, what formula would model its distance dd (in feet) from the starting point in terms of the time elapsed, tt (in seconds)? Recall that this does not necessarilly represent the actual relationship between the distance traveled and time elapsed for the real car. This represents the relationship for an imaginary car traveling at a constant speed.s = d/t

Answer 1

below

Explanation:

A. To find the constant speed that allows the car to travel exactly 144 feet in exactly 15 seconds, we can use the formula: speed = distance / time.

So, speed = 144 feet / 15 seconds = 9.6 feet/second.

B. If a car traveled at a constant speed of 9.6 feet/second for t seconds, the formula for its distance dd (in feet) from the starting point in terms of the time elapsed, tt (in seconds) would be:

dd = 9.6 feet/second * t seconds = 9.6t feet.