Question

Find the electric field of a long line charge at a radial distance where the potential is 24 V higher than at a radial distance r1= 3 m where E= 4 V/m. Ans. 29.5 V/m.

Answer 1

Answer: 36 V / r - 108 V/m = 29.5 V/m.

Explanation: Given that the electric field is 4 V/m at a radial distance r1 = 3 m, we can use the relationship between electric field and electric potential to find the electric potential at a radial distance where the potential is 24 V higher.

The electric potential V is related to the electric field E by the equation V = E * r.

So, at the new radial distance, the electric potential V = 24 V higher than at r1, so V = 24 V + E * r1 = 24 V + 4 V/m * 3 m = 36 V.

Now, we can use the relationship between electric field and electric potential to find the electric field at this new radial distance:

E = V / r = 36 V / r.

Solving for the electric field, we get:

E = 36 V / r = 36 V / (r - r1) = 36 V / (r - 3 m) = 36 V / r - 108 V/m.

So the electric field at this new radial distance is 36 V / r - 108 V/m = 29.5 V/m.

Hope this helps!