Question

the equilibrium constant for the reaction 2 hf (g) ⇌ h₂ (g) f₂ (g) is 0.440 at a particular temperature. what is the equilibrium constant for the equation ½ h₂ (g) ½ f₂ (g) ⇌ hf (g)?

Answer 1

The equilibrium constant for the equation ½ H₂ (g) + ½ F₂ (g) ⇌ HF (g) is the same as the equilibrium constant for the equation 2 HF (g) ⇌ H₂ (g) + F₂ (g), which is 0.440.

Step-by-step explanation:

The equilibrium constant (K) for a reaction is not affected by the coefficients in the balanced equation. Therefore, the equilibrium constant for the equation ½ H₂ (g) + ½ F₂ (g) ⇌ HF (g) is the same as the equilibrium constant for the equation 2 HF (g) ⇌ H₂ (g) + F₂ (g), which is 0.440. The coefficients in the equation do not change the value of the equilibrium constant.