Answer:
The balanced equation for the reaction is:
H2SO4 + 2 LiOH → Li2SO4 + 2 H2O
From the balanced equation, it can be determined that 2 moles of water are produced per mole of sulfuric acid. To find the mass of water produced from 10 g of sulfuric acid, we need to convert 10 g to moles and then multiply by the number of moles of water produced per mole of sulfuric acid.
The molar mass of sulfuric acid is 98 g/mol, so 10 g of sulfuric acid is 10 g / 98 g/mol = 0.102 mol.
Thus, 0.102 mol * 2 moles of water / 1 mole of sulfuric acid = 0.204 moles of water.
And finally, the mass of water produced is 0.204 moles * 18 g/mol (the molar mass of water) = 3.672 g.