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A car i traveling at 90 km/hr. In coming to a top, it ha an acceleration of -8. 0 m/^2. If the reaction time of the driver i 2. 5 , how far will the car travel before coming to a ret

User Sugrue
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Answer:

The distance traveled by an object under constant acceleration can be calculated using the equation:

d = v_0 * t + 0.5 * a * t^2

where d is the distance traveled, v_0 is the initial velocity (90 km/hr = 90 * 1000 / 60 / 60 = 25 m/s), t is the time elapsed, and a is the acceleration (-8.0 m/s^2).

First, we need to find the total time elapsed. The reaction time of the driver is 2.5 seconds, so the total time elapsed is:

t = t_r + t_a

t = 2.5 s + (v_f - v_0) / a

where t_r is the reaction time, t_a is the time taken for the car to come to a stop, v_f is the final velocity (0 m/s), and a is the acceleration (-8.0 m/s^2).

To find t_a, we need to solve for the time it takes the car to come to a stop (when v_f = 0 m/s):

0 = v_0 + a * t_a

t_a = -v_0 / a

t_a = -25 m/s / (-8.0 m/s^2) = 3.125 s

So the total time elapsed is:

t = 2.5 s + 3.125 s = 5.625 s

Next, we can use this value for t to find the distance traveled:

d = v_0 * t + 0.5 * a * t^2

d = 25 m/s * 5.625 s + 0.5 * (-8.0 m/s^2) * (5.625 s)^2

d = 141.5625 m

So the car will travel 141.5625 meters before coming to a stop.

Step-by-step explanation:

User Sevval Kahraman
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