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An amusement park has two payment options. Visitors to the park who use Plan A pay a $10 admission fee plus $3 for every ride they go on. Visitors who use Plan B pay a $20 admission fee and $1 per ride. What is the least number of rides a visitor must go on for Plan B to be less expensive?​

User Ysh
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Answer:

The least number of rides that a visitor would have to go on for Plan B to be cheaper would be four. This is because the admission on Plan B is $10 more than the admission on Plan A, and so if you went on more than four rides, you would have to pay more money than Plan A.

User Inno
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