Answer:
The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. To find the equation of the line given the point (-3, -1) and the slope of 2, we can use the point-slope form of a line: y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope. Plugging in the values, we have:
y - (-1) = 2(x - (-3))
y + 1 = 2x + 6
y = 2x + 5
So, the equation of the line that passes through the point (-3, -1) and has a slope of 2 is y = 2x + 5.