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Find the smallest number such that when its divided 14 , 12, 8 has a remainder of 3

1 Answer

4 votes

Answer:

171

Explanation:

First find the LCM of 14, 12 and 8

2 is a common factor for all three

14/2 = 7

12/2 = 6

8/2 = 4

We have 7 prime so we cannot factor further

The LCM is 7 x 6 x 4 = 168

Add 3 to 168 and that will be the smallest number that satisfies the requirement

168 + 3 = 171

171/14 : Quotient 12, remainder 3

171/12 : Quotient 14, remainder 3

171/8: Quotient 21, remainder 3

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