Question

Suppose I told you that (x+1) is a factor of (x²-6x-7). What would be a good idea to

obtain the other factor?
(x²-6x-7)(x+1)
(x²-6x-7)(x+1)
(x²-6x-7)(x+1)
(x+1)= (x²-6x-7)

Answer 1

Answer: Choice A.
`(\text{x}^2-6\text{x}-7) / (\text{x}+1)`

Reason:

We know that (x+1) is a factor of
`\text{x}^2-6\text{x}-7`

This means

`\text{x}^2-6\text{x}-7 = (\text{x}+1)*(\text{other factor})`

That rearranges to

`\text{other factor} = (\text{x}^2-6\text{x}-7) / (\text{x}+1)`

after dividing both sides by (x+1)

Use polynomial long division or synthetic division to find the other factor.