Question

a 3kg block slides at 2m/s along a flat floor. it collides and sticks with another 3kg block that was initially at rest. what what speed do the two blocks stuck together slide at after the collusion? (inelastic)

Answer 1

The final velocity of the two blocks after the collision can be determined by the law of conservation of momentum. The initial momentum of the first block (3 kg * 2 m/s) is equal to the final momentum of the two blocks together (mass_total * velocity_final). The total mass of the two blocks is 3 kg + 3 kg = 6 kg.

So, velocity_final = (3 kg * 2 m/s) / (6 kg) = 2/2 = 1 m/s.