Answer:To determine if the function is a minimum or maximum value, we need to find its second derivative and see if it is positive or negative. If the second derivative is positive, the function is a minimum value, if it's negative, the function is a maximum value.
The second derivative of the given function is a constant (2), which means it is always positive. Therefore, the function g(x)=x^2+6x+8 is a minimum value.
The minimum value occurs at the vertex of the parabolic shape of the function, which can be found using the formula: x = -b / 2a, where a, b, and c are the coefficients of the function g(x) = ax^2 + bx + c. Plugging in the values, we get x = -6 / 2 * 1 = -3.
The minimum value of the function can be found by substituting the x value back into the function: g(-3) = (-3)^2 + 6(-3) + 8 = 9.
So the minimum value of the function g(x) = x^2 + 6x + 8 is 9, and it occurs at x = -3.
Explanation: