Question

if the charge on the particle is 19.2 mc and it takes 66.0 j of work to move the particle between a and b, what is the magnitude of the potential difference between points a and b?

Answer 1

The potential difference between points A and B can be calculated using the equation V = W/Q, where V is the potential difference, W is the work done, and Q is the charge. In this case, W = 66 J and Q = 19.2 μC. Therefore, the potential difference is:

V = 66 J / 19.2 μC = 3.44 V.