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A man exerts a horizontal force of 145 N on a crate with a mass of 31.2 kg.

A man exerts a horizontal force of 145 N on a crate with a mass of 31.2 kg.-example-1

1 Answer

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Answer:

Below

Step-by-step explanation:

If you can't overcome the force of friction....the crate will not move

so friction force = 145 N

Coeff of friction = Ff / Normal force = 145 / (31.2 * 9.81) = .47

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