Question

3. By how many degrees Celcius would the temperature of 3 kg of a

substance change if the substance absorbed 4.328 kJ of energy?
Assume that the specific heat of the substance equals 0.630 J/g*C.

Answer 1

The temperature change of a substance can be calculated using the formula: Temperature change = Energy absorbed / (Mass of substance * Specific heat). In this case, the temperature of 3 kg of the substance would change by approximately 7.28 *
`10^{-4`°C.

Step-by-step explanation:

The temperature change of a substance can be calculated using the formula:

Temperature change = Energy absorbed / (Mass of substance * Specific heat)

In this case, the mass of the substance is 3 kg and it absorbs 4.328 kJ of energy. The specific heat of the substance is given as 0.630 J/g*C. To use this formula, we need to convert the mass from kg to grams. So, the mass of the substance is 3,000 grams.

Plugging the values into the formula:

Temperature change = 4.328 kJ / (3,000 g * 0.630 J/g*C)

Simplifying the equation, we get:

Temperature change ≈ 7.28 *
`10^{-4` °C

Therefore, the temperature of 3 kg of the substance would change by approximately 7.28 *
`10^{-4` °C.

Answer 2

Below

Step-by-step explanation:

3 kg = 3000 g and 4.328 kj = 4238 j

(units have to match units of given specific heat J/(g°C) )

4238 j / (3000 g * x °C) = .630 J / (g °C)

(4238 / .630 ) / 3000 = x °C

x = 2.24 °C