Question

What is the final concentration when 275mL of water is added to 155mL of 0.130M KCl?

Answer 1

Below

Step-by-step explanation:

.130 * .155 = initial number of moles of KCL

then add .275 liter of water bringing total volume to .275 + .155 = .430 Liter

moles of KCl divided by volume = concentration

.130*.155 / (.430) = .047 M