Question

HELP THIS IS FOR EXTRA CREDIT AND ITS DUE TODAY

You spin a spinner that is equally divided into 11 parts. 3 parts are green, 3 parts are speckled, 2 parts are white, and 3 parts are yellow.
What is the probability of the spinner not stopping at a white section? Write your answer as a decimal rounded to the nearest hundredth.

Answer 1

Answer: The probability of the spinner stopping at a green section and then rolling a 3 is 1/22

Step-by-step explanation: A spinner stopping at a green section

B: rolling a 3

the spinner is divided into 11 parts, 3 of them are green, then:

P(A) = 3/11

the number cube has 6 numbers, then:

P(B) = 1/6

The two events are independent, then:

P(A∩B) = P(A)*P(B) = 3/11 * 1/6 = 1/22