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A toy rocket is launched from a platform 39 feet above the ground at a speed of 83 feet per second. The height of the rocket in feet is given by the polynomial −16t2 + 83t + 39, where t is the time in seconds. How high will the rocket be after 3 seconds?

1 Answer

5 votes

Answer:

144 ft

Explanation:

Put in '3' where 't' is and compute

Height = -16(3^2) + 83(3) + 39 = 144 ft

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