Question

A 4260-kg roller coaster train full of riders approaches the level loading dock at a speed of 19.0 m/s. It is abruptly decelerated to a speed of 3.2 m/s. Determine the work done on the roller

coaster.
KE+PE+Wext=KE+ PE

Answer 1

below

Step-by-step explanation:

The change in Kinetic Energy is equal to the work done

KE = 1/2 mv^2

Change in KE = 1/2 m (19^2 - 3.2^2) = 747.1 kjoules