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Use stoichiometry calculations and show all work:

calculate how many grams of PbSO4 would be produced if 5.5 grams of LiNO3 were produced.
Reaction: Li2SO4(aq) + Pb(NO3)(aq) = 2LiNO3(aq) + PbSO4(s)

User Bjorn
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1 Answer

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Answer:

Step-by-step explanation:

The reaction you provided is a balanced chemical equation, meaning that for every mole of LiNO3 produced, an equal amount of PbSO4 is produced. However, since you only know the amount of LiNO3 produced (5.5 grams), you can use stoichiometry to find the amount of PbSO4 produced.

First, you need to convert the amount of LiNO3 to moles:

5.5 g LiNO3 / 6.939 g/mol = 0.796 mol LiNO3

Next, using the stoichiometry of the reaction, you can find the number of moles of PbSO4 produced:

0.796 mol LiNO3 * (1 mole PbSO4 / 2 moles LiNO3) = 0.398 moles PbSO4

Finally, you can convert the number of moles of PbSO4 to grams:

0.398 moles PbSO4 * 247.77 g/mol = 98.42 g PbSO4

So, if 5.5 grams of LiNO3 were produced, then 98.42 grams of PbSO4 would be produced.

User Helmut Zechmann
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