Question

A circuit with a battery, a 4 Ω resistor, a 15 Ω resistor, and a 22 Ω resistor in series. The total current is the system is 8.0 A. What is the voltage drop across the 4 Ω resistor?

Answer 1

Step-by-step explanation:

The voltage drop across a resistor in a series circuit is equal to the current through the resistor multiplied by the resistance.

The voltage drop across a resistor in a series circuit is equal to the current through the resistor multiplied by the resistance.V = I * R

The voltage drop across a resistor in a series circuit is equal to the current through the resistor multiplied by the resistance.V = I * RV (4 Ω resistor) = 8.0 A * 4 Ω = 32 V.