Question

A circuit with a 9 V battery and two 6 Ω resistors in series. What is the current throughout the circuit?

Answer 1

Answer: 0.75 amps

Step-by-step explanation:

Current= Voltage/Resistance

9/(6+6) = 9/12

9/12= 0.75

Answer 2

Step-by-step explanation:

The total resistance of the circuit is the sum of the individual resistances.

The total resistance of the circuit is the sum of the individual resistances.R_total = R1 + R2 = 6 Ω + 6 Ω = 12 Ω

The total resistance of the circuit is the sum of the individual resistances.R_total = R1 + R2 = 6 Ω + 6 Ω = 12 ΩThe current through a circuit is equal to the voltage divided by the resistance.

The total resistance of the circuit is the sum of the individual resistances.R_total = R1 + R2 = 6 Ω + 6 Ω = 12 ΩThe current through a circuit is equal to the voltage divided by the resistance.I = V / R

The total resistance of the circuit is the sum of the individual resistances.R_total = R1 + R2 = 6 Ω + 6 Ω = 12 ΩThe current through a circuit is equal to the voltage divided by the resistance.I = V / RI = 9 V / 12 Ω = 0.75 A.