Question

Find the midpoints of each of the sides of a triangle ABC, where A is (1, 1), B is (5,5) and C is (11,2).​

Answer 1

Midpoint AB

`(3, 3)\\`

Midpoint BC

`\left(8, \; (7)/(2)\right)`

Midpoint AC

`\left(6, \; (3)/(2)\right)`

Explanation:

The midpoint (x, y) between any two points(x1, y1) and (x2, y2) can be calculated using

x = (x1 + x2)/2
y = (y1 + y2)/2

Given
A(1, 1)
B(5, 5)
C(11, 2)

Midpoint of AB

`\left((1+5)/(2), \;(1+5)/(2)\right) = \left((6)/(2), \;(6)/(2)\right) = (3, 3)`

Midpoint of BC :

`\left((5+11)/(2), \;(5+2)/(2)\right) = \left((16)/(2), \;(7)/(2)\right) = \left(8, \; (7)/(2)\right)`

Midpoint of AC:

`\left((1+11)/(2), \;(1+2)/(2)\right) = \left((12)/(2), \;(3)/(2)\right) = \left(6, \; (3)/(2)\right)`