Given that in a △ABC, ∠A:∠B:∠C=11:5:4
Let the angles of the given triangle be 11xo,5xo,4xo.
We know that the sum of the angles of a triangle is 180o
11xo+5xo+4xo=180o⇒20xo=180o
xo=12110o=15o
So, the angles of the triangle are 70o,60o,45o.
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