Question

Triangle bac was dilated from triangle bde at a scale factor of 2. what proportion proves that cos∠d = cos∠a? triangles bde and bac, in which angle b is a right angle, point d is between points b and a, and point e is between points b and c; bd measures 2 units, be measures 3 units, and de measures 3 and 61 hundredths units. 2 over 3 and 61 hundredths = 4 over 7 and 22 hundredths three halves = six fourths 3 over 3 and 61 hundredths = 6 over 7 and 22 hundredths two thirds = four sixths

Answer 1

To prove that cos∠d = cos∠a, we can use the fact that the triangles BDE and BAC are similar triangles due to the dilation with a scale factor of 2.

Step-by-step explanation:

To prove that cos∠d = cos∠a, we can use the fact that the triangles BDE and BAC are similar triangles due to the dilation with a scale factor of 2.

Since angle B is a right angle, angle D in triangle BDE is complementary to angle A in triangle BAC. Therefore, cos∠d = sin∠a, because the cosine of an angle is equal to the sine of its complementary angle.

Therefore, the proportion that proves cos∠d = cos∠a is: sin∠a / sin∠d = 3 / 3.61, which simplifies to 3 / 3.61.

Answer 2

Answer:3/3.61 = 6/7.22

Step-by-step explanation:

got it right on the test