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A line contains the points (1, 1) and (3, 9). What is the equation of the line? Must be solved algebraically.​

A line contains the points (1, 1) and (3, 9). What is the equation of the line? Must-example-1

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Answer:

the equation of the line that contains the points (1, 1) and (3, 9) is y = 4x + 3.

Explanation:

To find the equation of the line that contains the points (1, 1) and (3, 9), we can use the slope-point form of the equation of a line, which is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line, m is the slope of the line, and (x, y) are any other points on the line.

We can use the first point (1, 1) and the slope of the line to find the equation of the line:

m = (9 - 1) / (3 - 1) = 4

y - 1 = 4(x - 1)

y = 4x + 3

So, the equation of the line that contains the points (1, 1) and (3, 9) is y = 4x + 3.

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