Question

Suppose that the perimeter of a rectangle is 34 feet, and the length is 7 feet more than the width. Find the width of the rectangle, in feet.

Answer 1

5 feet

Explanation:

Let's call the width of the rectangle "w". Then, the length would be "w + 7".

The perimeter of the rectangle is given as 34 feet, so we can set up an equation using the two sides of the rectangle:

2w + 2(w + 7) = 34

Expanding the second term and simplifying the equation, we get:

2w + 2w + 14 = 34

4w + 14 = 34

4w = 20

w = 5

Therefore, the width of the rectangle is 5 feet.