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5 votes
Find the median and mean of the data set below: 21 , 40 , 48 , 26 , 32 , 31

User Robskrob
by
8.6k points

2 Answers

4 votes

Explanation:

21, 26, 31, 32, 40, 48

Median

31+32= 63

63÷2= 31.5

Mean

21+26+31+32+40+48=198

198÷6=33

User Geoandri
by
8.0k points
2 votes

What does the problem asks for:

--> mean and median

Let's calculate the mean:


\text{Mean}=\frac{\text{sum of all the numbers}}{\text{number of numbers given}}

--> the sum of all the numbers = 21 + 40 + 48 + 26+ 32 + 31 = 198

--> number of numbers given: 6

==> let's calculate


\text{Mean}=(198)/(6) =33

Let's calculate the median

--> Median definition: middle number in an ordered sequence

==> let's order the sequence: 21, 26, 31, 32, 40, 48

--> since there are an even number of numbers, there isn't an exact

middle number

--> thus, we must find the mean of the two numbers closest to the

middle


\text{Median} = (31+32)/(2) =(63)/(2) =31.5

Answer: 31.5

User Clorichel
by
8.2k points

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