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A line has a slope of – 9 and includes the points ( – 9,1) and ( – 10,q). What is the value of q?

User Hop Hop
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To find the value of q, we can use the point-slope form of a line:

y - y1 = m(x - x1)

where m is the slope of the line, (x1, y1) is a point on the line, and (x, y) is a second point on the line.

In this case, we have the slope of the line as -9 and the point ( -9, 1), so we can plug in the values:

y - 1 = -9 (x - (-9))

Expanding and solving for y, we get:

y = -9x + 90

Next, we want to find the value of y when x = -10. Substituting this value into the equation:

q = -9(-10) + 90

Solving for q:

q = -90 + 90 = 0

So, the value of q is 0.

User Cavita
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