Question

Find the distance. In units, between P and Q Express the answer as a square root

P(-4,2)
Q(2,4)

Answer 1

`~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P(\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad Q(\stackrel{x_2}{2}~,~\stackrel{y_2}{4})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ PQ=√((~~2 - (-4)~~)^2 + (~~4 - 2~~)^2) \implies PQ=√((2 +4)^2 + (4 -2)^2) \\\\\\ PQ=√(( 6 )^2 + ( 2 )^2) \implies PQ=√( 36 + 4 ) \implies PQ=√( 40 )`