Answer: y - ln2 = (1/2)(x - 2) or y = (1/2)x + ln2 - 1
Explanation:
f(x) = lnx
f'(x) = 1/x
f(2) = ln 2 , so we have the slope = 1/2, and a point (2, ln2)
equation of tangent:
y - ln2 = (1/2)(x - 2)
y = (1/2)x + ln2 - 1
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